To find the measure of ∠BDC in the figure, it is helpful to recognize that the sides BC and AD are parallel (definition of trapezoid) and are connected by the transversal BD. ∠CBD and ∠ADB are alternate interior angles, and thus are equal and both measure 25°. Because A, D, and E all lie along the same line, ∠ADE = 180°. Because ∠ADE is made up of ∠ADB, ∠BDC, and ∠CDE, you know that the measures of these three angles add up to 180°. If x is the unknown angle measure, then 25° + x + 125° = 180°; thus x is equal to 30°.

You can apply common sense to solve this problem. If the average of 7 consecutive integers is 16, it would make sense that the middle number is 16 (this assumption only holds because there are an odd number of integers and because the integers are consecutive). Thus, the list of consecutive integers is 13, 14, 15, 16, 17, 18, 19. The sum of the first and last integers is 13 + 19 = 32.

Recall that the area of a circle with radius r is πr². The radius of the circle can be found by taking half of the distance across the circle, which in this case is also equal to half of the length of the side of the square. Thus the area of the square is π6² = about 113 square feet. If you selected answer choice A you found the area of the square.

You are given that x divided by 7 leaves a remainder of 4. The easiest approach to this problem is to assume that 7 goes into x one time, with a remainder of 4. Therefore, x is equal to 11. If x = 11, then 2x = 22. When 22 is divided by 7, the remainder is 1.

For the product of two integers to lie between 137 and 149, a multiple of both integers must lie between 137 and 149. Of the answer choices, 15 is the only number without a multiple that lies between 137 and 149; 15 × 9 = 135, and 15 × 10 = 150. Thus, the only number that cannot be one of the integers is 15.

To find the y-intercept of the line −9x − 3y = 15, convert the equation to slope-intercept form. To so do, first add 9x to both sides to get −3y = 9x + 15. Then divide by −3 to get y = −3x − 5. Since the slope-intercept form of the equation is y = −3x − 5, the slope is −3 and the y-intercept is −5.

To solve this problem, first recognize that, since \(\overline{XY}\) = \(\overline{YZ}\), the triangle is isosceles. Because the triangle is isosceles, you know that angles X and Z are congruent and have equal measure. If a = 40°, then 180° = 40° + x° + y° and x° + y° = 140°. Since x = y, both angles equal 70◦. In triangles, sides have lengths that are proportional to their opposite angles. Because you know that the length of \(\overline{XZ}\) is 5, and \(\overline{XZ}\) is opposite the 40° angle, you can set up a proportion to find the length of side \(\overline{XY}\) using its opposite angle, 70°, as follows:
5/40 = \(\overline{XY}\)/70
5 = 40(\(\overline{XY}\)/70)
(5 × 70) = 40\(\overline{XY}\)
= 350/40 = 8.75

To solve this problem, recognize that the triangle is a “special triangle.” A right triangle in which the length of the longer leg is √3 times the length of the shorter leg is a 30◦−60◦−90◦ right triangle. Another property of this type of right triangle is that the hypotenuse is 2 times the length of the shorter leg. So, this right triangle has lengths x, x √3, and 2x. The perimeter is the sum of the lengths of the sides. You are given that the perimeter equals 12 + 4 √3. Set the two equations equal and solve for x:

12 + 4√3 = x + x√3 + 2x
12 + 4√3 = 3x + x√3

For the right side of the equation to equal the left side of the equation, x must be equal to 4.

To solve the equation M = 6T + 5 for N you could subtract 5 from both sides to get M − 5 = 6N, and then divide by 6 on both sides to get \(\frac{(M − 5)}{6}\).

To find the length BC when the length AD is 32 units, the length AC is 23 units, and the length BD is 27 units, and the points are along the segment AD as shown in the problem, you must notice that segment BC is the intersection of segment AC and the segment BD. So, the sum of the lengths AC and BD is the same as the sum of the lengths AD and BC. Using the actual lengths, solve for BC as follows:
AC + BD = AD + BC
23 + 27 = 32 + BC
50 = 32 + BC
18 = BC