For the function f(x) = x2 e–x, the maximum occurs when x is equal to
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Solution
How many graphs on n labelled vertices exist which have at least (n2– 3n)/2 edges?
The number of different n × n symmetric matrices with each element being either 0 or 1 is{Note :Power (2, x) is same as 2x}
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Solution
Let A, B, C, D be n × n matrices, each with non-zero determinant. If ABCD = l, then B–1 is
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Solution
Let P(E) denotes the probability of the event E. Given P(A) = 1, P(B) = 1/2, the values of P(A/B) and P(B/A)respectively are
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Solution
Consider the following routing table at an IP router.
For each IP address in Group I identify the correct choice of the next hop from Group II using the entries from the routing table above.
Which of the following is true about a transparent router ?
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Solution
Router is used to connect LAN to WAN.
Let R be a relation, which of the following comments about the relation R is/are correct?
1.R will necessarily have a composite key, if R is in BCNF but not in 4 NF.
2.If R is in 3 NF and if every key of R is simple, then R is in BCNF.
3.If R is in BCNF and if R has at least one simple key,then R is in 4 NF.
4.If R is in 3 NF and if its every key is simple, then R is in 5 NF.
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Solution
All the given statements above the relation Rare true. Hence,the correct answer is option(d).
You have a class C 193.158.12.0/28 network. How many usable subnets and hosts do you have?
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Solution
Class C 193.158.12.0/28 network means there are 28 bits in the subnet.So, the subnet mask is
11111111.11111111.11111111.11110000.
There are 4 bits belonging to the subnet and 4 bits belonging to host in the fourth octet.
So, 4 bits of subnet mask corresponds to
(24 – 2) = 16 – 2 = 14 subnets
and 4 bits belonging to host address corresponds to
(24– 2) = 16 – 2 = 14 hosts.
A 4 km long broadcast LAN has data transfer rate of 108 bps and uses CSMA/CD. The signal travels along the UTP wire at 2 × 108 m/s. What is the minimum packet size that can be used on this network?
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Solution
L = R × d⁄v bits = 2000 bits.