The slip of an induction motor normally does not depend on
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Solution
he second harmonic component of the periodic waveform given in the figure has an amplitude of
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Solution
Given signal is, half wave symmetry,so even harmonics will be zero.Hence 2nd harmonic =0
The system represented by the input-output relation
\(y(t)=\int_{-\infty }^{\infty }x(\tau )d\tau ,t>0)\) is-
Solution
Given,\(y(t)=\int_{-\infty }^{\infty }x(\tau )d\tau\)
The system is linear because the principles of homogeneity and super position hold for integration operator.
The system is not causal because the output depents upon the future value.
The RMS value of the voltage u(t) = 3 + 4 cos (3t) is
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Solution
In the figure given below the value of R is
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Solution
If E is the electric field intensity,then \(\bigtriangledown\). (\(\bigtriangledown\) × E) is equal to
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Solution
As the electric field is conservative in nature.Hence, \(\bigtriangledown\) × E = 0
\(\bigtriangledown\). (\(\bigtriangledown\)× E) = Null vector
In the figure given below, the initial capacitor voltage is zero. The switch is closed at t= 0, the final steady state voltage across the capacitor is
For the two-port network shown in the figure given below, the z-matrix is given by
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Solution
A dc over compound generator is supplying power to an infinite bus. If prime mover is accidentally cut off, then dc machine will
A synchronous machine connected to infinite but bars is initially delivering active power to and absorbing laggingre active power from the bus bars. As increase in the power input to the synchronous machine will cause a/an
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Solution