QUESTIONS CARRY TWO MARKS EACH.
For an SCR, the gate-cathode characteristic has a straight line passing through the origin with as lope of 130 Volt/amp. For a trigger source voltage of 15 V and allow able gate power dissipation of 0.5 watts, the required gate source resistance will be __________.
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Solution
QUESTIONS CARRY TWO MARKS EACH.
The frequency of the pulse at z in the network shown in figure below is __________.
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Solution
10-bit ring counter is a MOD-10, so it divides the 160 kHz input by 10, therefore, w= 16 kHz. The four-bit parallel counter is a MOD-16. Thus, the frequency at x = 1 kHz.The MOD-25 ripple counter produces a frequency at y =40 Hz. (1 kHz/25 = 40 Hz). The four-bit Johnson Counter is a MOD-8 This, the frequency at z = 5 Hz.
QUESTIONS CARRY TWO MARKS EACH.
For the circuit shown below the value of io is __________.
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Solution
QUESTIONS CARRY TWO MARKS EACH.
In a Q-meter measurement to determine the self-capacitance of a coil, the first resonance occurred at f1 with C1= 300 pF. The second resonance occurred at f2= 2f1 with C2= 60 pF. The self-capacitance (pF) of coil works out to be __________.
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Solution
QUESTIONS CARRY TWO MARKS EACH.
A system has the following transfer function
\(G(s)=\frac{100(s+15)(s+50)}{s^{4}(s+12)(s^{2}+3s+10)}\)The type and order of the system are respectively
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Solution
The s has power of 4 and denominator has order of 7. So type 4 and order 7.
An audio amplifier is designed to have a small signal band width of 20 kHz. The open loop low-frequency voltage gain of the op-amp is 105 and unity gain bandwidth is 1MHz. What is the maximum closed-loop voltage gain for this amplifier.
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Solution
Bodep lot for the frequency response of op-amp is given following
Here, CL×|ACL|max = fμ × 1
fCL → close loop Band-width
fμ → unity gain bandwidth
|ACL|max → maximum closed loop gain
(20 × 203) |ACL|max = 1 × 106
|ACL|max = 50
QUESTIONS CARRY TWO MARKS EACH.
The op–amp shown in figure, has a slew rate of 1V/ns,what is the higest input frequency for which no slewing occurs.
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Solution
QUESTIONS CARRY TWO MARKS EACH.
The forward-path transfer function of a ufb system is
\(G(s)=\frac{K(s+2)}{(s+3)(s^{2+2s+2})}\)The angle of departure from the complex poles is
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Solution
QUESTIONS CARRY TWO MARKS EACH.
The logic realized by the circuit shown in the figure below is
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Solution