For a product,the forecast for the month of January was 500 units. The actual demand turned out to be 450 units.The forecast for the month of February (Smoothing coefficient = 0.1) will be ________.
-
Solution
As we know that,Ft= αAt – 1+ (1 –α) Ft – 1
where Ft = Forecast for current time period ‘t’
Ft – 1= Forecast for period before current time period
α = Weight ranging between 0 and 1
At – 1= Actual demand for the period before current time period ‘t’
Here,α= 0.1,
A2t – 1= 450, Ft – 1= 500
Ft= 0.1 × 450 + (1 – 0.1) 500
= 45 + 450 = 495
Two radiating surfaces A1= 6 m2 and A2= 4 m2 have the shape factor F1–2= 0.1, the shape factor F2–1 will be________
-
Solution
The critical speed of shaft is affected by the
-
Solution
At critical speed, the shaft starts vibrating execssively and having a transverse direction so the diameter and span of shaft are main factors to affect the critical speed.
Why are babbit alloys used for bearing material ?
-
Solution
Babbit alloys are used for bearing materials because they have excellent embeddability and suitability.
The purpose of helical groover in a twist drill is to
A.Stiffness improvement
B.Save a tool material
C.Provide space for chip removal
D.Provide rate angle for cutting edge Select correct answer using codes given below :
-
Solution
The purpose of helical grooves in a twist drill is to provide rake angle for cutting edge and space for removing chips for passing cutting fluids.
Match List I with List II.
List I List II
A.Electropolishing 1.Thermal
B.Electro-chemical 2.Mechanical machining
C.Abrasive jet machining 3.Electro-chemical
D.Electricaldischarge 4.Chemical
machining Codes :
-
Solution
Base process Unconventional machining process
Chemical = Electropolishing
Elecro-chemical = Electro-chemical machining
Mechanical = Abrasive jet machining
Thermal = Electric discharge machining
In a turning solid round bar,if the travel of the cutting tool in the direction of feed motion is 1000 mm, rotational speed of the work piece is 500 rpm and feed role in 0.2mm/rev, then the machining time will be …………….
-
Solution
In arc welding, the arc length should be equal to
-
Solution
In arc welding,
Arc length =3⁄2 × rod diamter
It m is the number of constraints in a linear programming with two variables x and y and non-negativity constraints x> 0, y> 0, the teasible region in the graphical solution will be surrounded by how many lines ?
-
Solution
Number of lines in a graphical solution
= Number of non-negativity constraints = m+ 2
Which are of the following is correct ? In a sensible heating or cooling process ?
-
Solution
Humidity ratio remains constant in a sensible heating or cooling process.