Consider the following statements -The shear stress over a beam section of any shape for a given loading does not vary with
1.Area of the section
2.Shear force at the section
3.Moment of inertia of the section
Which of these statements are correct.
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Solution
Degree of kinematic indeterminacy of the structure is _____.Consider members to be inextensible.
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Solution
Match the following types of level ling with their approx.permissible error’s. Where K is the distance in Kms
(A) Rough levelling 1. ±1√K to ±4√K
(B) Accurate levelling 2. ±12√K
for benchmark
establishment
(C) Ordinary levelling, ±3.24√K
construction surveys
(D)Precise levelling 4.±100√K
Which of the following causes fatigue failure in a structure
1.Large number of loading cycles
2.Maximum stress
3.Residual stress
4.Wide range of stress variation Select the correct answer using the codes given below :
The alkalinily and the hardness of water sample are 250mg/lit and 250 mg/lit as CaCO3 respectively. The water has
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Solution
Alkalinity = 250 mg/lit
Hardness = 250 mg/lit
So, carbonate hardness = 250 mg/lit
Non-carbonate hardness=Total hardness
– Carbonate hardness
= 250 – 250
= 0.
Which one of the following has loose bearing capacity
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Solution
Bearing capacities can be nearly addressed as:
Loose gravel = 25000 kg/m2
Hard rock = 3,30,000 kg/m2
Softrock = 45,000kg/m2
Compact gravel = 45,000 kg/m2
If the operating head on an ogee spill way is more than the design head, then
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Solution
When operating head is more than designated head then cavitation will occur.When operating head is less than designated head then positive pressure will develop on the crest,discharge coefficient will be reduced resulting in reduced discharge.
The velocity profile for a turbulent boundry layer is given by \(\frac{u_{x}}{u}=\left ( \frac{y}{\delta } \right )^{1/5}\) for y ≤ δ.The shape factor for this turbulent boundry layer shall be
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Solution
A pipeline, 200 m long carries water. Velocity of propagation of pressure wave is 1000m/sec. If the valve at the down-stream end is instantaneously closed at time t = 0 negative water hammer pressure at the valve will last for
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Solution
The close-coiled spring shown in figure 1 is cut into two equal pieces which are combined to form a parallel sping as shown in figure 2. The ratio of angular twist for the sping in figure 1 to that of sping in figure 2 due to axial load W is
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Solution