QUESTIONS CARRY ONE MARK EACH.
For a soil condition calculate the effective stress at 3m el-evation. Assume rw=10kN/m2
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Solution
QUESTIONS CARRY ONE MARK EACH.
A concrete column causes an avail load of 450 kN and a bending moment of 60 kNm at its base. An isolated footing of size 2m × 3m side along the plate of the bending moment is provided under the column center of gravity of column and footing coincide. The net maximum and minimum pressures in kN/m2 on soil under footing are respectively.
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Solution
QUESTIONS CARRY ONE MARK EACH.
Abeam is made up of two identical bars AB and BC, by hinging them together at B. The and A is builtin(cantilevered) and end C is simply supported. With the load P acting as shown, the bending moment at A is
QUESTIONS CARRY ONE MARK EACH.
A steel portal frame has dimensions, plastic moment capacities and applied loads as shown in the figure. The vertical loads is always twice the horizontal load. The collapse load P required for the development of beam mechanism is
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Solution
QUESTIONS CARRY ONE MARK EACH.
For the frame shown in the figure, the maximum BM in the column is
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Solution
QUESTIONS CARRY ONE MARK EACH.
The value of \(\oint \frac{1}{(1+z^{2})}dz\), where C is the contour \(\left | z-\frac{i}{2} \right |=1\) is
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Solution
QUESTIONS CARRY ONE MARK EACH.
The order of error in the Simpson’s rule for numerical integration with step size h is
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Solution
Error in simpson’s rule is of order h4.
QUESTIONS CARRY ONE MARK EACH.
In a game, 2 players X and Y,toss a coin alternatively.Who sever gets a ‘head’ first, wins the game and game is terminated. Assuming that player X starts the game, then the probability of player X winning the game is
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Solution
QUESTIONS CARRY ONE MARK EACH.
The solution of the differential equation \(\frac{d^{2}y}{dx^{2}}+2\frac{dy}{dx}+2y=0\) are
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Solution
QUESTIONS CARRY ONE MARK EACH.
Given an orthogonal matrix A= \(\begin{bmatrix} 1 &1 &1 &1 \\ 1 &1 &-1 &1 \\ 1 &-1 &0 &0 \\ 0 &0 &1 &1 \end{bmatrix}\) (AAT-1) is
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Solution
∵ It is orthogonal matrix,
by property
AAT= I = ATA
∴ (AAT-1) = (I)-I
= I