Oscillator circuit shown in the figure given below
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Solution
The transistor shunt regulator shown in the figure given below has a regulated output voltage of 10 V,when the input varies from 20 V to 30V. The relevant parameters for the zener diode and the transistor are :
Vz= 9.5 V, VBE= 0.5 V,β= 99.
Then maximum power dissipated in the zener diode(Pz)and the transistor (PT) are
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Solution
Z parameters Z11 and Z21 for the 2-port network given in the figure below are
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Solution
A plane wave is characterized by
\(\vec{E}=(0.5\hat{x}+\hat{y}e^{j\pi /2})e^{j\omega t-jkz}\)This wave is
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Solution
The system shown in figure given below remains stable when
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Solution
Voltage gain \(A_{v}\overset{\Delta }{=}\frac{V_{0}}{V_{i}}\) of the JEET amplifier shown in
figure given below is
[IDSS = 10 mA; Vp = – 5V(assume C1, C2 and Cs to be very large)]
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+18
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–18
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+6
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–6
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Solution
A zener diode in figure given below is to be designed to meet the specifications :
IL= 10 mA, V0= 10 V and
Vin varies from 30 V to 50 V.
Zener diode has Vz= 10 V and
Izk(knee current) = 1 mA.
For satisfactory opermation
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R ≤ 1800 Ω
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2000 Ω ≤ R ≤ 2200 Ω
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3700 Ω ≤ R ≤ 4000 Ω
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R > 4000 Ω
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Solution
Circuit given in figure employs positive feedback and is intended to generate sinusoidal oscillation.
If at a frequency \(f_{0},B(f)\overset{\Delta }{=}\frac{V_{f}(f)}{V_{0}(f)}=\frac{1}{6}\angle 0^{\circ}\), then to sustain oscillation at this frequency
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R2 = 5R1
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R2 = 6R1
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R2 = R1⁄6
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R2 = R1⁄5
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Solution
If a plane electromagnetic wave satisfies the equation \(\frac{\partial ^{2}E_{x}}{\partial z^{2}}-c^{2}\frac{\partial ^{3}E_{x}}{\partial t^{2}}\), then wave propagates in the
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x-direction
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z-direction
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y-direction
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xz plane at an angle of 45° between the x and z directions
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Solution
Equations for electric and magnetic fields for a plane EM have propagating in the Z-direction
If characteristic equation of a closed-loop system is s2+ 2s+ 2 = 0, then the system is
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over damped
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critically damped
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underdamped
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undamped
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Solution
Characteristic equation of a closed-loop system is
s2+ 2s+ 2 = 0
∴ wn= √2
and δ = 1⁄√2 < 1, Hence, underdamped system