Match List-I with List-II
List-I List-II
A.Procurement cost 1.cost of holding materials
B.Carrying cost 2.cost of receiving order
C.EOQ 3.procurement lead time
D.Reorder point 4.break even analys is
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Solution
Procurement cost = cost of receiving order
Carrying cost = cost of holding materials.
EOQ = break even analysis.
Re-order point = procurement lead time.
The inter arrival times at a tool crib are exponential with an average time of 10 min and length of service time is assumed to be 6min. Then the probability that a person arriving at the booth will have to wait equal to –
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Solution
In economics of machining, which one of the following costs remain constant?
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Solution
Tool handling cost per piece remains constant in economics of machining. This cost comes under the category of unproductive costs.
A circular solid shaft is subjected to bending moment of 400kN-m and a twisting moment of 300 kN-m. On the basis of maximum principle stress theory,the directs tress is sand according to the maximum shear stress theory, the shear stress is τ. Then the ratio of directs tress shear stress \(\frac{\sigma }{\tau }\left ( \frac{direct\: stress}{shear\: stress} \right )\) will be ________
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Solution
Eight bolts are to be used for fixing the cover plate of a cylinder subjected to a maximum load of 980.175 kN. If the design stress for the bolt material is 315 N/mm2, then the diameter of each bolt will be _________.
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Solution
In an axial flow compressor, α1 and α2 are exist angle and inlet angle with stator and β1, β2 are inlet and outlet angle with rotor. Then the condition for having a 50% degree of reaction will be:
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Solution
Condition for having 50% degree of reaction is given as :α1 = β2,β1= ∝2
A pitot tube (c= 1) is used to measure air flow with water in the differential manometer and a gauge difference of 72 mm,then the value of air speed if density = 1.18 kg/m3.
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Solution
In an assembly line, the rate of arrival of products is 0.8 parts/minute. Processing time with mean is 1.8 min. with exponential distribution. Then the probability, that a random part arrival finds that there are 9 parts already exist in the system, will be ________.
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Solution
In an operation of NC work table, the following data is given:
Pitch of a leads crew = 9 mm
Gear ratio = 8 : 1
Number of pulse generated = 58 pulses/rev.
Distance moved by the table = 230 mm
Feed rate = 430 mm/min.
Then the number of pulses received by the controlsystemfor purpose of verification for the movementof tablethroughenact distance of230 mm will be ________.
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Solution
The specification for a hole is φ54\(\overset{0.060}{0.000}\)mm. The mating shaft has a clearance fit with minimum clearance of 0.04 mm.If the tolerance on the shaft is 0.08 mm, then the maximum clearance in mm between the shaft and the hole will be________.
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Solution
Given:Hole specification: φ54\(\overset{0.060}{0.000}\)mm
Minimum clearance = 0.04 mm
Tolerance on shaft = 0.08 mm
Hole size = 54.000 – 54.060
Maximum shaft size = 54.000 – 0.04 = 53.96 mm
Minimum size of shaft = 53.96 – 0.08= 53.88 mm
Maximum clearance= 54.060 – 53.88
= 0.18 mm