Number of boys in tennis club | Number of boys in basketball club |
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Solution
Ratios do not furnish any information about actual numbers.
Ratio of number of Red to non-red Marbles in jar | 1⁄2 |
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Solution
Out of every 7 marbles, 3 are red, 4.are non red.
So the ratio is 3 : 4 which is greater than 1 : 2.
Ratio of red to Blue marbles now | 4 : 7 |
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Solution
Side B is 4⁄7 = .57
When we add one marble each to side A the ratio will be always more than .57
paul’s age in 1988 | 12 |
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Solution
Let Paul's age in 1980 be x.
∴ John's age = 8x Linda's age = 3x
∴ 8x - 3x = 20 ∴ x = 4
∴ Paul's age in 1980 = 4 years
∴ Paul's age in 1988 = 12 years.
In the figure above, all line segments meet to form right angles.
Perimeter of figure | 52 |
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Solution
x + x + 1 + x + 2 + x + 3 = 14
Y + Y + Y + Y = 12
Perimeter = 2(12 + 14) = 2 × 26 = 52
0, P, Q are centres of three circles, all lie on diameter AB.
Area of entire shaded region | 4 times the area of unshaded region |
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Solution
Col. A -
Let radius of smallest circle be r.
∴ Radius of middle circle and largest circle is 2r and 4r respectively.
Col. A -
π(4r2) - π(2r)2 + πr2 = 16πr2 - 4πr2 + πr2 = 13πr2
Col. B-
4(area of unshaded region) = 4 × [ π(2r)2 - πr2] = 12πr2
Three circles have same centre. Radii of circles are 3, 4, 5.
Area of region R | Area of region P |
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Solution
Col. A = πr2 = π32 = 9π
Col. B = 25π - 16π = 9π
The average of measures of 3 angles of a triangle whose largest angle measures 79° | The average of measures of 3 angles of the triangle whose smallest angle measure 43° |
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Solution
Sum of angles of any triangle = 180°
∴ Average = 60°
\(\sqrt{m+n}\) | \(\sqrt{m}+\sqrt{n}\) |
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Solution
Squaring both sides
Col. A = m + n
Col. B = m + n + 2\(\sqrt{mn}\)
Since 2\(\sqrt{mn}\) = positive
Number of people between jack & jill | 79 |
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Solution
Jack's ranking from front = 25. Jill's ranking from last = 39.
= 143 - 25 - 39 = 79