Imagine line segment BC free to move so that B remains stationary, and C moves towards or away from D. We will not affect the ratio AB/AD but will get different rations for DC/CB. Hence this is a D choice.

The extra numbers in the series on in the left column are -6 to 6. When we add these up the total is zero (-6 + 6, -5 + 5, -4 + 4 etc.). And so both sums will be the same.

The maximum difference between the numbers will come if we make x as large as possible (just a little less than 8), and make y as small as possible (a little greater than 3).
The maximum difference will, therefore, have to be a little less than 5.

The x-coordinate of P is negative.
The Y-coordinate of P is positive (and is therefore greater)

If the mean of four numbers is 20, then their sum must be 20 x 4 =80
If the sum of three of them is 60, them the fourth number = 80 - 60 = 20

We can find the volume of a rectangular block by multiplying the area of the base by the height. But in this case the height is not known. Do not assume that the sides of the faces must be squares. If they are square, the volume = 16 x 5 = 80. But let us assume that one face is 16 x 1 and the other face is 20 x 1. Then the volume becomes 16 x 20 x 1 = 320.

R > P > V, and S > T
Also R>T>P. Integrating this picture we have R>T>P>V with S occurring in the list somewhere before T. This is the problem - we do not know exactly where to put S. So we cannot decide whether S and V will have more money than R and T.

5 less than 4x can be written 4x - 5
4x - 5 = 27; 4x = 32; x = 8

The sectors next to the 7 must be assigned 8.
Next to these 8s there must be 7s.
Between the 7.s there must be an 8 = x

Since two angles are given we can find the third. 180 - 59 - 61 = 60
Now we need to realize that the largest angle is opposite the longest side.
AB is opposite angle ACB, which is the largest.