No. of revolutions it makes | 20 |
-
Solution
Area = πr2 = 9⁄π. ∴ r = 3⁄π
Circumference = 2πr = 6ft.
∴ No. of rev. = \(\frac{120}{6}\) = 20
The sum of the positive divisors of 17 | The product of positive divisors of 19 |
-
Solution
Col. A ⇒ 1 + 17 = 18
Col. B ⇒ 1 × 19 = 19
C2 | a2 + b2 |
-
Solution
Total of all angles is 18x.
∴ x = 100
∴ Angles are 1000 ,300 ,500
∴ c2 must be greater than a2 + b2
(Rule: In a right angle Δc2= a2 + b2
But if angle c is greater than angle a + angle b, then c2 > a2 + b2)
A rectangle ground above has a pavement of 1 meter along all four sides.
Area of Pavement | 14 s . meters |
-
Solution
Area of ground 8 × 5 = 40 sq meters. Area of ground with pavements around the ground
10 × 7 = 70 sq. meters.
∴ Area of pavement = 30 sq. meters.
Max. value of α – β | 1020 |
-
Solution
αβ = 1225
Min. value of β = 1 and Max. value of α = 1225
∴ Col. A = 1225 -1 = 1224
Column A | Column B |
-
Solution
\(\left ( \frac{1}{7} \right )^{\theta }\frac{1}{\sqrt{19}}=7\times \frac{1}{7}-19\times \frac{1}{19}=0\)
Quantity of water added to 270 ml of 20% alcohol to give 10% concentration. | 220 ml |
-
Solution
To reduce the alcohol to 10%, quantity of water should be doubled.
∴ Addition will be 270 m!.
Number of 5 cent stamps used | Number of 7 cent stamps used |
-
Solution
Since we have to buy 5 cent stamps, value of 7 cent stamps must be a multiple of 5.
∴ John can buy 5 stamps of 7 cents and 8 stamps of 5 cents or 10 stamps of 7 cents and 1 stamp of 5 cents.
∴ 5 cent stamps can be either 8 or l.
Number of tanks 5 men clean in 3 minutes | 20 |
-
Solution
10 more people can clean 30 more tanks in the same time i.e. 3 minutes,
∴ 5 people must be cleaning 15 tanks in 3 minutes..
Perimeter of triangle ABC | 37 |
-
Solution
BD = 4, DC = 12 ∴ BC = 16
∴ Perimeter = 35