Remainder when N is divided b 6 | 2 |
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Solution
Using BODMAS rule N = (17 × 14 × 39 × 43) - 2
Consider \(\frac{17 \times 14 \times 39\times 43}{6}\) = 17 × 7 × 13 × 43
Which is an exact multiple of 6.
∴ (17 × 14 × 39 × 43) - 2 when divided by 6 gives a remainder of 4
n | 10 |
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Solution
History and Geography books can be held together as one unit.
∴ There are 3 units -
I(H, G), IS, lA which can be arranged among themselves in 3! number of ways.
Also the History and Geography books can be arranged among themselves in 2! number of ways.
∴ n=2! × 3!= 12
Product of all distinct prime factors of 52 | Product of all distinct prime factors of 63 |
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Solution
52 = 2 × 2 × 13
Distinct primes are 2 and 13.
∴ Col. A = 2 × 13 = 26
63 = 3 × 3 × 7
Distinct primes are 3 and 7.
∴ Col. B = 3 × 7 = 21
x | y + z |
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Solution
Let ∠ABC = C
y + z = C
Now we have to decide which angle is greater x or c. But it will depend on the position of C.
(10)2x-1 | x(10)-2 |
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Solution
Col. A = \(\frac{100}{x}\),Col.B =\(\frac{x}{100}\)
Let x = 0.5
∴ Col. A > col. B
Let x = 100, Col. A = Col. B
Let x = 200, Col. A < Col. B
x | y |
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Solution
Let Y = 2 ∴ y2 = 4
∴ x2 = 9 ∴ x = ±3
If x = +3 Ans: (A)
If x = -3 Ans: (8)
Number of stones needed to cover the walkway | 120 |
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Solution
Area of the walkway = (76 × 64) - (64 × 52)
= 64 (76 - 52) = 64 × 24 m2
∴ Number of stones needed
=\(\frac{64\times 24}{4\times 3}\)=16 × 8 = 128
The number of people who had worked at least 10 years and did not respond that they were discontented with the jobs | 800 |
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Solution
36% of 3000 = 1080 employees are discontented. 25% of 1080 = 270 have been working for last 10 years.
Total number of employees working for last 10 years = 45% of 3000 = 1350
∴ Col. A = 1350 - 270 = 1080 employees did not respond that they were discontented
∴ Col. A = 1080, Col. 8 = 800
The additional profit in $, the bank must now make, so that amount of profit per employee remains same | \(\frac{kn}{m}\) |
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Solution
Last year, each employee got k⁄m dollars.
This year, the bank has m + n employees.
Profit per employee = k⁄m
∴ Total profit this year must be k⁄m × (m + n)
= k + \(\frac{kn}{m}\)
∴ Additional profit = \(\frac{kn}{m}\)
The % increase in profit per TV set over the previous year | 22 |
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Solution
Assume that, initially the dealership sold 100 TV sets at a $100 profit per TV set.
∴ Total profit = 100 × 100 = $10000
Next year, it sold 90 TV sets and earned a total profit of 10000 × 1.1 = $11000
∴ Selling price of 1 TV = \(\frac{11000}{90}\) = \(\frac{1100}{9}\) = 122.22
∴ %increase = 22.22% ∴ Col. A > Col. 8