DIRECTIONS: These are Assertion-Reason type questions.Question contains two statements:Statement-1 (Assertion) and Statement-2 (Reason). Answer these questions from the following four options.
Statement-1 : o and p-nitrophenols can be separated by steam distillation.
Statement-2 : o-nitrophenol have intra molecular hydrogen bonding while p-nitrophenol exists as associated molecules.

Statement- 1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement -1
Statement -1 is True, Statement -2 is True ; Statement-2 is NOT a correct explanation for Statement - 1
Statement - 1 is True,Statement- 2 is False
Statement -1 is False, Statement -2 is True

Solution

o and p-nitrophenols can be separated by steam distillation because o-nitrophenol is steam volatile due to presence of weak intramolecular hydrogen bonding where as p-introphenol contains inter molecular hydrogen bonding.Here, both statement-1 and statement-2 are correct and statement-2 is correct explanation of statement-1.

In which case hydrogen bond will not be observed

H₃O₂^-
H₂O
H₅O₂⁺
H_3/sub>O⁺

Solution

The enolic form of a acetone contains

9 sigma bonds, 1 pi bond and 2 lone pairs
8 sigma bonds, 2 pi bonds and 2 lone pairs
10 sigma bonds, 1 pi bond and 1 lone pair
9 sigma bonds, 2 pi bonds and 1 lone pair

Solution

a
b
c
d

Solution

A ? bonded molecule MX₃ is T-shaped. The number of non bonded pair of electrons is

zero
2
1
can be predicted only if atomic number is known

Solution

For T-shape geometry the molecule must have 3 bonded pair and 2 lone pair of electrons.

The correct order of bond energies in NO, NO+ and NO–is:

NO^- > NO > NO⁺
NO > NO^- > NO⁺
NO⁺ > NO > NO^-
NO⁺ > NO^- > NO

Solution

The common features among the species CN^–, CO and NO⁺are

bond order three and isoelectronic
bond order three and weak field ligands
isoelectronic and weak field ligands
None of these

Solution

The molecules BF₃ and NF₃ are both covalent compounds,but BF₃ is non polar whereas NF₃ is polar. The reason for this is

atomic size of Boron is larger than nitrogen
Boron is metal while nitrogen is gas
B – F bonds are non-polar while N – F bonds are polar
BF₃ is planar but NF₃ is pyramidal

Solution

Molecular shapes of SF_{4/sub>, CF₄ and XeF₄ are}

the same, with 2, 0 and 1 lone pairs of electrons respectively
the same, with 1, 1 and 1 lone pairs of electrons respectively
different, with 0, 1 and 2 lone pairs of electrons respectively
different, with 1, 0 and 2 lone pairs of electrons respectively

Solution

In compounds of type ECl₃, where E = B,P,As or Bi, the angles Cl – E- Cl for different E are in the order.

B > P = As = Bi
B > P > As > Bi
B < P = As = Bi
B < P < As < Bi

Solution

In the anion HCOO^– the two carbon – oxygen bonds are found to be of equal length. What is the reason for it ?

Electronic orbitals of carbon atom are hybridised
The C = O bond is weaker than the C –O bond
The anion HCOO^- has two resonating structures
The anion is obtained by removal of a proton from the acid molecule

Solution

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