In which of the following electronic configuration an atom has the lowest ionisation enthalpy?
One of the characteristic properties of non-metals is that they
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Solution
Non metals form oxides with oxygen and thus reduce oxides of metals behaving as reducing agents.
Which of the following sets has strongest tendency to form anions ?
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Solution
N, O and F (p-block elements) are highly electronegative non metals and will have the strongest tendency to form anions by gaining electrons from metal atoms.
Which of the following is not the correct order for the stated property ?
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Solution
On moving along the period, ionization enthalpy increases.
In second period, the order of ionization enthalpy should be as follows : F > O > N But N has half-filled structure, therefore, it is more stable than O. That’s why its ionization enthalpy is higher than O. Thus, the correct order of IE is F > N >O.
An element of atomic weight 40 has 2, 8, 8, 2 as the electronic configuration. Which one of the following statements regarding this element is not correct
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Solution
Its valency is 2. So it will form MO type compound.
Which transition involves maximum amount of energy?
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Solution
The energy involved is ionisation energy (I.E.). Further the 3rd ionisation energy will be greater than the 2nd and 1st.
Which of the following sequence correctly represents the decreasing acidic nature of oxides ?
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Solution
On passing from left to right in a period acidic character of the normal oxides of the elements increases with increase in electronegativity.
The outermost electronic configuration of the most electronegative element is
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Solution
Halogens are most electronegative.
Which of the following is the most electronegative?
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Solution
F,because of its smallest size.
The largest size of the ion is :
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Solution
Chlorine and sulphur are in period three. Potassium and calcium are in period four.As K has radius more than calcium, K+ ion will have largest size.