Practice Test 10
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  • Solution

    Cu + H2SO4 ⟶ CuSO4 + H2 (as acid)
    H2 + H2SO4 ⟶ 2H2O + SO2 (as oxidant)
    In (a), H2SO4 acts just as dehydrating agent.
    In (b), it acts just as an oxidant.
    In (d), it neither acts as oxidant nor as acid.

In oxygen difluoride, the oxidation number of oxygen is :

  • Solution

    Let oxidation state of oxygen in OF2= x
    ∴ x+ ( – 1 × 2) = 0
    ∴ x= + 2

In haemoglobin the iron is in the following oxidation state :

  • Solution

    In haemoglobin, Fe is in +2 oxidation state.

One mole of N2H4 loses 10 moles of electrons to form a new compound, y. Assuming that all nitrogen appear in the new compound, what is the oxidation state of nitrogen in y (There is no change in the oxidation state of hydrogen )

  • Solution

The oxidation states of the most electronegative element in the products of the reaction, BaO2 with dil. H2SO4 is

  • Solution

    BaO2 + H2SO4 ⟶ BaSO4 + H2O2
    Oxygen is the most electronegative element in the reaction and has the oxidation states of–1 (in H2O2)and –2 (in BaSO4). In H2O2, peroxo ion is present.

  • Solution

Which of the following statements is not correct?

Which of the following involves a redox reaction?

  • Solution

In which of the following reaction, oxidation number of N remains unchanged ?

  • Solution

    The oxidation number of N in NO2 is +4 and in N2O4 is also + 4(i.e. no change)

The oxide, which cannot act as a reducing agent, is

  • Solution

    Carbon has the maximum oxidation state of + 4,therefore carbon dioxide (CO2) cannot act as a reducing agent.

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Redox Reactions
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