DIRECTION: These are Assertion-Reason type questions. Question contains two statements:Statement-1 (Assertion) and Statement-2 (Reason). Answer these question from the following four options.
Statement-1 :Pb4+ compounds are stronger oxidizing agents than Sn4+ compounds.
Statement-2 :The higher oxidation states for the group 14 elements are more stable for the heavier members of the group due to ‘inert pair effect’
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Solution
Assertion is true because lower oxidation state becomes more & more stable for heavier elements in p-block due to inert pair effect. Hence Reason is false.
DIRECTION: These are Assertion-Reason type questions. Question contains two statements:Statement-1 (Assertion) and Statement-2 (Reason). Answer these question from the following four options.
Statement-1 :Silicones are hydrophobic in nature.
Statement-2 :Si – O – Si linkages are moisture sensitive.
DIRECTION: These are Assertion-Reason type questions. Question contains two statements:Statement-1 (Assertion) and Statement-2 (Reason). Answer these question from the following four options.
Statement-1 :Benzene is reactive while inorganic benzene is unreactive compound.
Statement-2 :Inorganic benzene is, borazine, B3N3H6
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Solution
Borazine has more polarity as compared to benzene because nitrogen is more and boron is less electronegative than carbon. Thus due to polarity inorganic benzene, borazine is highly reactive while benzene is much less reactive.
DIRECTION: These are Assertion-Reason type questions. Question contains two statements:Statement-1 (Assertion) and Statement-2 (Reason). Answer these question from the following four options.
Statement-1 :Boron is metalloid.
Statement-2 :Boron shows metallic nature.
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Solution
Boron is metalloid. Thus assertion is correct. Metalloids possess,metallic as well as non-metallic nature. Hence,reason is false.
The species present in solution when CO2 is dissolved in water are
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Solution
CO2 + H2O ⇌ H2CO3 ⇌ H+ + \(HCO_{3}^{-}\) ⇌ 2H+ \(CO_{3}^{2-}\)
How can the following reaction be made to proceed in forward direction?
B(OH)3 + NaOH ⇌ NaBO2 + Na[B(OH)4] + H2O
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Solution
When PbO2 reacts with conc. HNO3 the gas evolved is
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Solution
PbO2 is a powerful oxidizing agent and liberate O2 when treated with acids.
2PbO2 + 4HNO3 ⟶ Pb(NO3)2 + 2H2O + O2 ↑
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Solution
Negative ΔrG° value indicates that + 2 oxidation state is more stable for Pb. Also it is supported by inert pair effect that + 2 oxidation state is more stable for Pb and as ΔrG° value is positive in second reaction it indicates that + 4 oxidation state is more stable for Sn.i.e., Sn++ < Pb++, Sn4+ > Pb4+.
Heating an aqueous solution of aluminium chloride to dryness will give
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Solution